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WHAT TO DO:

HOW TO DO IT:

Given a trinomial of type ax^{2} ± bx ± c that has at
least one common factor. Factor out all of the common
factors then look at the remaining quadratic trinomial.

k·(Ax^{ 2} ± Bx
± C)

Given a general trinomial:

72x^{ 2} − 60x − 28

Factor out common factor if there is one.

4(18x^{ 2} − 15x − 7)

On Scratch Paper, look at polynomial inside (...):

18x^{ 2} − 15x − 7

Use GN and Clue of Signs

Multiply first and last coefficients:

GN

18·7 = 126

NOTE: Last sign is − therefore

Find all pairs of factors of 126 with
difference of 15.

The largest factor of the pair gets sign of
middle term, −

the other is positive:

− 21 and + 6

Rearrange polynomial using these values
as coefficients of x

18x^{2} − 21x + 6x − 7

Factor common factor from each group:

3x(6x − 7) + 1(6x −7)

Combine with first term factored out
the complete factors of: 72x^{2} - 60x - 28